What is the common difference of an arithmetic sequence if its algebraic form is 2n+1/3
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Answer:
D = Common Difference = 2/3
Explained Below
Step-by-step explanation:
- I Think It Should Be Like [2n+1]/3
- Put Integral Values Of n , Either Positive Or Negative
- If n = 1 , t1 = [2(1)+1]/3 = 3/3 = 1
- If n = 2 , t2 = [2(2)+1]/3 = 5/3
- If n = 3 , t3 = [2(3)+1]/3 = 7/3
- Common Difference D => t3-t2 or t2-t1
- Let's Take t3-t2 For A Simpler Calculation
- 7/3-5/3 = D = 2/3
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