Question

What is the completely factored form of 3x5 – 7x4 + 6x2 – 14x

Answer 1

3${x}^{5}$ - 7x⁴ + 6x² - 14x

_________ [ GIVEN ]

• We have to factorised it completely.

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→ 3${x}^{5}$ - 7x⁴ + 6x² - 14x

Take x common from it

→ x(3x⁴ - 7x³ + 6x - 14)

Now take 3x - 7 common from it.

→ x[(3x - 7) (x³ + 2) +(3x - 7) (x³ + 2)]

→ [x (3x - 7) (x³ + 2)]

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[x (3x - 7) (x³ + 2)] is the completely factorised form of 3${x}^{5}$ - 7x⁴ + 6x² - 14x.

__________ [ ANSWER ]

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Answer 2

Answer:

The final answer is $x(3x-7)(x^3-2)$

Step-by-step explanation:

$3x^5 -7x^4+6x^2-14x$

To find the factors of the above expression, We simply have to find the common terms with which we could divide the whole expression. W

We find out that the common term with the expression is x. So we take x as common and the expression changes to.

$x(3x^4-7x^3+6x-14)$

Then we take 3x - 7 as the common term next in the equation and the equation changes to

$x(3x-7)(x^3-2)$

This equation cannot be factorized any further.

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