what is the compound intrest of 1000 rs at rate of 10% in 3 year
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SI = 1000×10×1÷100
SI = 100
A = 1000+100
= 1100
SI = 1100×10×1÷100
= 110
A = 1100+110
= 1210
SI = 1210×10×1÷100
=121
A =1210+121
= 1331
CI= 1331-1000
= 331 Answer
OR
CI= P[(1+r÷100)^3- 1]
=1000[(1+10÷100)^3-1]
= 1000[(1+1÷10)^3-1]
=1000[(11÷10)^3-1]
=1000[1331÷1000-1]
= 1000[331÷1000]
=1000×331÷1000
=331 Answer
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