what is the concentration in ppm selenium if 1.3 mg is found in 2500 kg of soil
Answers
Answered by
3
Answer:
0.52
Explanation:
1.3 x 10^-3/2500×10^6 = 0.52
Answered by
4
Answer:
0.00052
Explanation:
mass of solute=1.3mg/0.0000013kg or 1.3×10^-6kg
mass of solution = 2500kg .
we know , ppm =
(mass of solute/mass of solution)×10⁶
= (0.0000013/2500) × 10⁶
= 0.00000000052 × 10⁶
= 0.00052
hope it helped
thanks !!
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