What is the concentration of sugar (C₁₂H₂₂O₁₁) in mol L⁻¹ if its 20 g are dissolved in enough water to make a final volume up to 2L?
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the concentration of sugar (C12H22O11) in mole L-1 if it's 20 g are dissolve in enough water to make a final volume up to 2L.
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The most straightforward approach to answer this inquiry is to initially make sense of the molar mass of the sugar being referred to.
To do this increases the quantity of individual particles for a given component by its nuclear mass.
12 X 12.01 g/mol = 144.12 g/mol C
22 X 1.008 g/mol = 22.176 g/mol
H 11 X 16.00 g/mol = 176.00 g/mol
O Total = 342.296 ~ 342.30 g/mol
C12H22O11.
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