what is the conclusion of the activity when potassium iodide is added to lead nitrate solution?
Answers
Answered by
2
a yellow precipitate is formed that is lead iodide (PbI)
it's eqn will be
Pb(NO3)2 + KI ---- PbI + KNO3
it's eqn will be
Pb(NO3)2 + KI ---- PbI + KNO3
Similar questions