Question

What is the conjugate of √3-5?

Answer 1

Answer:

The answer is $\sqrt 3+5$

Step-by-step explanation:

The conjuage of any number of the form $a-b$ is $a+b$

(Just change sign of one of the term).

So conjugate of $\sqrt 3-5$ is $\sqrt 3+5$

Note : $-\sqrt 3-5$ can also be taken as the conjuagate of $\sqrt 3-5$