what is the correct option?
please explain step by step.
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which St standard are you in
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Answer:
P = Q
Step-by-step explanation:
I am using A in place of theta
In case of set P
sinA - cosA =√2cosA
sinA = cosA(√2+1)
tanA = √2+1
A = arctan(√2+1)
in case of Q
sinA + cosA = √2sinA
cosA = sinA(√2 -1)
tanA = 1/(√2 -1)
on rationalising with {√2+1) we gat
tanA = (√2+1)/(2-1)
tanA = √2+1
A = arctan(√2+1)
thus we can see that both P and Q have same set of solutions and each member of P is a member of Q and vice versa
so P= Q
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