what is the covalency state of nitrogen in NO2
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Here's the answer to your question.
Let us take oxidation state of N in NO2 is x
so
x + (-2)×2 = 0 (because the compound is neutral)
x = +4
So the oxidation number of N in NO2 is +4 and covalency is also +4
Let us consider the oxidation state of N in N2O4 is y
So
2y + (-2)×4 = 0
2y = 8
y= +4
So oxidation state of N in N2O4 is +4 and covalency is also +4.
Hope it helps :)
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