What is the cube of 63in column method
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(60+3)^3
(x+y)^3=x^3+3(x^2y)+3(xy^2)+y^3
=60^3+3(60^2 3)+3(60 3^2)+3^3
=216 000+32 400+1620+27
=250 047=63^3
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(x+y)^3=x^3+3(x^2y)+3(xy^2)+y^3
=60^3+3(60^2 3)+3(60 3^2)+3^3
=216 000+32 400+1620+27
=250 047=63^3
Pls mark this as the Brainleist
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