What is the cube root of 0.009?explain with process.
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8
0.009 = 9/10³
√0.009 = ∛9 /10 = 2.080 /10 = 0.2080...
Find ∛9.000 as follows:
2 . 0 8 0
================
9. 000 000 000
2^3 8 2^3 < 9 2^4 > 9. so "2"
=====
1 000
12 0 0 0 000 3 * 2^2 = 12 * 100 = 1200 > 1000. So "0"
======
1 000 000
124, 864 998 912 3 *20^2*100 +3*20*8*10+8^2 = 124,864. So "8"
========
1 088
4,326, 4 0 0 0 000 3*208^2*100+3*208*1*10+0^2 > 1088 so "0"
=====
1 088
√0.009 = ∛9 /10 = 2.080 /10 = 0.2080...
Find ∛9.000 as follows:
2 . 0 8 0
================
9. 000 000 000
2^3 8 2^3 < 9 2^4 > 9. so "2"
=====
1 000
12 0 0 0 000 3 * 2^2 = 12 * 100 = 1200 > 1000. So "0"
======
1 000 000
124, 864 998 912 3 *20^2*100 +3*20*8*10+8^2 = 124,864. So "8"
========
1 088
4,326, 4 0 0 0 000 3*208^2*100+3*208*1*10+0^2 > 1088 so "0"
=====
1 088
kvnmurty:
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