what is the cube root of (-1)
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Answer:
It's -1 itself
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3 roots
1 real 2 imaginary
Real: x=-1
For imaginary
(x+1)(x2-x+1)=0
Solve x2-x+1 for others
1 real 2 imaginary
Real: x=-1
For imaginary
(x+1)(x2-x+1)=0
Solve x2-x+1 for others
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