What is the current flowing in a 5Ω resistor when a 5V battery is connected with it? If
in the above circuit one more 5Ω resistor is connected in series, then what will be the
value of current flowing through the circuit?
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Answer:
1 A
Explanation:
given resistence = 5 ohm
potential difference = 5V
w. k. t
V = IR
I = V/R
I = 5/5
I = 1A
if 5 ohm resistor connected in series then
equivalent resistance = 5+5 = 10 ohm
now, I = V/R
I = 5/10
I = 0.5 A
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