Question

what is the current flowing through the 10 ohms resistor in the figure below?

Answer 1

Answer:

applying kvl

first in loop ABCDE

−3i−6(i−i

1

) + 4.5=0 . -------(1)

then in loop ABCMNE

−3i−10i

1

−3+4.5=0 . --------(2)

From equation (1) and (2) WE GET,

i

1

=0

hence current passing through 10 ohm resistor is ZERO