What is the current if 4ohm and 2 ohm resists are connected in series and 6v potential difference is applied ?
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As The resistors are in series connection,
Thus,
R(net)=R1+R2
=>Rnet=4+2 ohm
=>R net=6 ohm
We know,
V=IR
=>I=V÷R
=>I=6÷6 A
=>I= 1Ampere (ans)
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