What is the current if the charge on a capacitor is halved?
Answers
Answer:
Explanation:
The formula for the capacitance of a parallel plate capacitor is
C=ϵA/x
where ϵ is the permittivity of the medium between the plates, A is the overlapping area of the two plates and x is the uniform separation between the plates.
Capacitance, intuitively, is the ability of a pair of conductors separated by a dielectric to store electrostatic energy - or in other words, how much charge the conductors can store at a given voltage level. It is analogous to the capacity of a bucket being how much water it can hold.
Q=CV
Assuming that the capacitor is connected across a constant voltage source keeping V constant,
As seperation between the conductor is halved(X is Halved),value of Capacitance(C) is Doubled.
Since charge is directly proportional to Capacitance(Q=CV),Charge on the parallel Plate Capacitor Doubled.