Question

what is the De Broglie wavelength associated with an electron accelerated through a potential difference of 100 volts ​

Answer 1

Answer:

wavelength=√150/V in Å

Answer 2

${\huge{\underline{\underline{\mathcal{\red{♡ANSWER♡}}}}}}$

• Acceleration potential ${V=100 v}$ .The de Broglie wavelength $\lambda{is}$
• $\lambda{h/p}$=$\frac{1.227}{\sqrt{V}}$ nm
• $\lambda$=$\frac{1.227}{\sqrt{100}}$ nm=${0.124nm}$.
• The de Broglie wavelength associated with an electron in this case is of the order of X-ray wavelengths.