Question

What is the de-Broglie wavelength associated with
the hydrogen electron in its third orbit :-
(1) 9.96 x 10-20 cm (2) 9.96 x 10-8 cm
(3) 9.96 x 104 cm (4) 9.96 x 108 cm​

Answer 1

Answer:

2

Explanation:

$mvr = (nh) \div 2\pi$

$mv = h \div \gamma$

$\gamma = wavelength$

$r = 0.529 {n}^{2} angstron$

0.529×n×2π= wavlenght