Question

what is the de broglie wavelength of an electron with kinetic energy 6eV

Answer 1

Here is your Answer :

$λ=</p><p></p><p> \frac{h}{ \sqrt{2mE } }$

$= \frac{6.6 \times {10}^ { - 34 } }{ \sqrt{2 \times 9.11 \times {10}^{ - 31} \times 6 \times 1.6 \times {10}^{ - 19}} }$

= calculate