Question

what is the deceleration of a vechicle moving in a striate line that changes its velicity from 100km/h to a dead stop 10seconds​

Answer 1

$\huge {\underline{\pink{Given:-}}}$

• Initial velocity ,u = 100km/h = 100×5/18 = 500/18 = 27.77 m/s

• Final velocity ,v = 0m/s

• Time taken ,t = 10 s

$\huge {\underline{\purple{To Find:-}}}$

• Deceleration of vehicle ,a

$\huge {\underline{\blue{Solution:-}}}$

As we know acceleration is defined as the rate of change in velocity at per unit time.

Negative acceleration is called deceleration .

• a = v-u/t

where,

a is the acceleration/deceleration

v is the final velocity

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 0-27.77/10

→ a = -27.77/10

→ a = -2.77m/s²

Therefore,the deceleration of the vehicle is 2.77m/s².

$\huge{\sf{\green{Additional\ Information !!~~ }}}$

Some equation of motion are

• v = u +at

• s = ut +1/2at².

• v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

Answer 2

=> v = u + at

=> v-u/t = a

=> a = v-u/t

=> a = 0-27.77/10

=> a = -27.77/10

=> a = -2.777m/s²

Deceleration of vehicle 2.777 m/s².