what is the derivative of 3^3x+7?????????
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Using formula a^bx = ba^bx ln a
We get,
3^3x+7 = 3x+7 * 3^3x+7 ln 3
We get,
3^3x+7 = 3x+7 * 3^3x+7 ln 3
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Hey there,
Derivative of 3³ˣ⁺⁷ is 3*3³ˣ⁺⁷*log3
Derivative of 3³ˣ⁺⁷ is 3*3³ˣ⁺⁷*log3
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