Question

What is the derivative of 3x²-1 by using first principle?

Answer 1

Answer:

hey can I give you answer.......

the answer is 42z I guess I am answering because I want pointsok?......enjoy

Step-by-step explanation:

here is the explanation byeeeebye

Answer 2

let

y = 3x^2 - 1

let ∆x be small change in x and ∆y be corresponding change in y

y + ∆y = 3 (x + ∆x)^2 - 1

y + ∆y - y = 3 (x + ∆x)^2 - 1 - 3x^2 + 1

∆y = 3 (x^2 + 2 x ∆x + (∆x)^2 - 3x^2

∆y = 3x^2 + 6 x ∆x + 3 (∆x)^2 - 3x^2

∆y = 6 x ∆y + 3 (∆x)^2

∆y / ∆x = 6x + 3∆x

applying limit both side ∆x tend to 0

limit ∆y/∆x = limit. (6x + 3 ∆x)

∆x-->0. ∆x -->0

dy/dx = 6x + 0

dy/dx = 6x