what is the derivative of e^x+log_e(x)
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Answered by
1
Answer:
Step-by-step explanation:
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Answered by
0
Answer:
Step-by-step
Answer:
x+2
x
Explanation:
This can be significantly simplified first using logarithm rules. The first we will use is that log(AB)=log(A)+log(B), so:
y=ln(x2ex)=ln(x2)+ln(ex)
Since ln(x)=loge(x) and ex, are inverse functions, we see that ln(ex)=x. Furthermore, we will also use log(AB)=Blog(A) for ln(x2):
y=2ln(x)+x
Now, to differentiate this, we must know that
d
dx
ln(x)=
1
x
. Thus:
dy
dx
=
2
x
+1=
x+2
x
explanation:
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