Question

what is the derivative of |x-3| at x=-1​

Answer 1

Answer:

Step-by-step explanation:

We know that ∣x∣=x for all x≥0 and ∣x∣=−x for all x<0. Therefore,

At x=2,

∣x−1∣=x−1 and ∣x−3∣=−(x−3)=−x+3

⇒f(x)=(x−1)+(−x+3)=2

which is a constant function and the derivative of a constant function is always zero. So at x=2 derivative of f(x) is zero.

Answer 2

Step-by-step explanation:

We know that ∣x∣=x for all x≥0 and ∣x∣=−x for all x<0. Therefore,

At x=2,

∣x−1∣=x−1 and ∣x−3∣=−(x−3)=−x+3

⇒f(x)=(x−1)+(−x+3)=2

which is a constant function and the derivative of a constant function is always zero. So at x=2 derivative of f(x) is zero.

plz mark me brainlist