what is the diameter of a cylinder placed between two wooden blocks.the inner edge of the blocks are 13cm. and 17.4cm.
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mass of the wooden block = m= 5 kgdimensions = 40 cm × 20 cm × 10 cm
the weight of the wooden block applies a thrust on the table top.That is,Thrust = F = mg= 5 kg × 9.8 m/s²= 49 N
Area of a side = length × breadth
= 20 cm × 10 cm
= 200 cm²
= 0.02 m²
Pressure = thrust/ area
Pressure = 49 /0.02= 2450 N/m²
The same thrust in implied when it lies on the given dimension.
Area= length × breadth= 40 × 20= 800= 0.08 m²
Explanation:
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