what is the difference between power rated and power consumed by a bulb?
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Suppose, An electric bulb is rated as 230 V AC, 100 W ( This is called rating of bulb i.e 100 W,). if this bulb is given supply of 230 V AC it will dissipate 100 W energy in one hour.
Now as per ohm’s law - V=I * R
and power P = V * I
so, p = V* I = V * V/R = V.V/R = I * I * R = I.I.R
so Resistance of the bulb R = V.V/P = 230 *230/100=529 ohms
so rated current I = V/R = 230/529 = 0.434 Amps
Now suppose if voltage available is 200 V
then P = V*V/R= 200 * 200/529 =75.6 W ( this is power dissipation at input voltage of 200 V)
shreyasharma39:
thank you!!!
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