Question

What is the difference between the sum of the first 2,019 even natural numbers and the first 2,019 odd natural numbers? ​

Answer 1

Sum of first 'n' odd numbers =n^2.soanswer is 2019×2019=4076361

Or else you can use this step by step process.

Take it as arthimetic progression.

1+3+5+……

First we have to find last number.

Last term=a+(n-1)d.

Last term=1+(2019–1)2=4037

So series is 1,3,5,……4037.

Sum of n terms in A.P is n/2[2a+(n-1)d]

=2019/2[2(1)+(2019–1)2]

2019/2(4038)=4076361

Answer 2

Answer:

4038

Step-by-step explanation:

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