Question

What is the difference in energy levels of the sodium atom if emitted light has a wavelength of 589nm

Answer 1

Answer:

there no difference as per mee

Answer 2

Answer:

$\Delta E=3.3749\times 10^{-19}\ J$

Explanation:

$\Delta E=\frac {h\times c}{\lambda}$

Where,  

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light

Given, $\lambda=589\ nm=589\times 10^{-9}\ m$

Thus, applying values as:

$\Delta E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589\times 10^{-9}}\ J$

$\Delta E=\frac{10^{-26}\times \:19.878}{10^{-9}\times \:589}\ J$

$\Delta E=3.3749\times 10^{-19}\ J$