What is the difference in energy levels of the sodium atom if emitted light has a wavelength of 589nm
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Dear Student,
◆ Answer -
∆E = 3.9×10^-40 J
● Explaination -
Difference in energy levels of the sodium atom is calculated by -
∆E = hν
Substitute ν = 589 nm = 589×10^-9 m,
∆E = 6.626×10^-34 × 589×10^-9
∆E = 3.9×10^-40 J
Therefore, the difference in energy levels of the sodium atom is 3.9×10^-40 J.
Thanks dear. Hope this helps you...
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