What is the Differentiation of x^2 Cosx
Answers
Answered by
1
Hey!!!...Here is ur answer
x^2 cosx
d/dx (x^2 cos x)
=x^2 d/dx (cos x) + cos x d/dx (x^2)
= - sin x .x^2 + 2x.cos x
=2x cosx-x^2sinx
Hope it will help you
x^2 cosx
d/dx (x^2 cos x)
=x^2 d/dx (cos x) + cos x d/dx (x^2)
= - sin x .x^2 + 2x.cos x
=2x cosx-x^2sinx
Hope it will help you
Answered by
2
Hola User ________________
Here is Your Answer ........
__________________________
Basically here
Y= X^2.Cosx
So actually here using the Product rule we get .......
dy/dx = x^2. d (cosx)/dx + cosx .d (x^2)/dx...
there fore ......
dy/dx = x^2.-sinx + cosx.2x......
so basically we get ....,,
x^2.-sinx+ cosx.2x
____________________________
Hope it helps u................☺✌
Here is Your Answer ........
__________________________
Basically here
Y= X^2.Cosx
So actually here using the Product rule we get .......
dy/dx = x^2. d (cosx)/dx + cosx .d (x^2)/dx...
there fore ......
dy/dx = x^2.-sinx + cosx.2x......
so basically we get ....,,
x^2.-sinx+ cosx.2x
____________________________
Hope it helps u................☺✌
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