What is the dimensional formula of E=mc2 ?
Answers
[ML^2 T^-2] = [M] [LT^-1]^2
[ML^2 T^-2] = [ML^2 T^-2]
Answer:
The dimensional formula of E = m is ML²T⁻²
Explanation:
From the above question,
They have given :
E = m
where, E is energy,
m is mass and
c is the speed of light.
The dimensional system of E=mc² can be derived the use of the dimensional evaluation method, the place we analyze the dimensions of every variable in the equation.
The dimension of power can be represented as [M L² T⁻²], the place M is mass, L is length, and T is time.
The dimension of mass can be represented as [M].
The dimension of the pace of mild (c) can be represented as [L T⁻¹].
Substituting these dimensions into the equation E=mc², we get:
[E] = [M L² T⁻²]
[m] = [M]
[c] = [L T⁻¹]
Therefore,
[E] = [m][c]²
[M L² T⁻²] = [M][L T⁻¹]²
Simplifying this expression, we get:
[E] = [M L² T⁻²]
Hence, the dimensional method of E=mc² is [M L² T⁻²].
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