Science, asked by nishu94, 1 year ago

what is the dimensional formula of polarization density

Answers

Answered by KartikSharma13
0
The electromagnetic field in the absence of matter, that is, in the "vacuum," is excellently described classically by Maxwell's theory, which is relativistically correct, in terms of the fundamental field vectors E and B. There is an equally successful quantum field theory. In both cases, however, we must introduce sources of the field, and these sources lie in matter, the rigorous description of which is extremely difficult. In Maxwell's theory, charge is introduced as the source of the electromagnetic field, and is idealized to point and continuous distributions. Matter is separated into conductors and dielectrics depending on whether the fields can penetrate into the matter. Conductors carry free charges that move to positions of equilibrium in response to the fields, but cannot leave the matter. Dielectrics are presumed to contain bound charges that cannot move freely, but can shift positions when in the presence of the field, which exerts forces upon them, producing polarization, and nonuniform polarization gives rise to new sources of the field. Simple laws are postulated to account for these effects, such as the dielectric constant κ that relates the D and E vectors: D = κE (we'll define these vectors later, but they are probably familiar to you). This theory is called phenomenological because all the parameters are empirical, and are not defined in terms of the constitution of the matter.

diiiixit2: he just asked formula
Answered by diiiixit2
1
Its dimensional formula is (L-2AT)
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