Question

What is the dipole movement of BeF2

Answer 1

Answer is 0.

Becoz Beryllium is an electropositive element while fluorine is an electronegative element. Therefore, the Be-F bond will have appreciable polar character. However, BeF2 is a non-polar molecule and its dipole moment is zero

Answer 2

$\bold{ \huge{Dipole \: moment:-}}$

=> Dipole moment is the product of the magnitude of the charge and the distance between the centres of positive (+) and negative (-) charge.

In short:-

The polarity of Covalent bond results in the form of electric dipole passing a permanent dipole moment which is defined as :

=> Dipole Moment (u)= charge (Q)×distance of separation (r)

=> It is expressed in Or it's C.G.S unit :- Debye (D)

S.I unit:- C-M

=> It is vector Quantity and is pointing towards (-ve) end.

=> The dipole moment of BeF2 is zero.

Explanation :-

The dipole moment of BeF2 is zero because it is linear in shape .It is a linear molecule. In BeF2 F is more electronegative than Be so due to equal and opposite vectors It's resultant dipole moment is zero.

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