Question

what is the
displacement vector of
the particle that
that moves from point p
(2, 3, 5) to point q (3,4,5)?​

Answer 1

$\large\maltese\:\underbrace{{\pmb{\frak{Answer:-} }}}$

• $\sf \hat{i}+\hat{j}$

$\large\maltese\:\underbrace{{\pmb{\frak{Solution:-} }}}$

We are given that, the initial position of the vector was p(2, 3, 5) and the final position was q(3, 4, 5) and we are asked to find the displacement vector.

The initial position vector can be written in its component form as:-

$\\\dashrightarrow \sf P(2,3,5) = 2\hat{i}+3\hat{j}+5\hat{k}$

Similarly, The final position vector can be written in its component form as:-

$\\\dashrightarrow \sf P(3,4,5) = 3\hat{i}+4\hat{j}+5\hat{k}$

Now, the displacement is calculated by :-

$\leadsto\underline{\boxed{\sf displacement = final \:position- initial\:position}}\bigstar$

$\\:\implies\sf displacement = 3\hat{i}+4\hat{j}+5\hat{k} - 2\hat{i}+3\hat{j}+5\hat{k}$

$\\:\implies\sf displacement = (3-2)\hat{i}+(4-3)\hat{j}+(5-5)\hat{k}$

$\\:\implies\boxed{\boxed{\sf displacement = \hat{i}+\hat{j}}}\bigstar$

Answer 2

Answer:

Explanation:If a particle moves from

P(2,3,5)=2

i

^

+3

j

^

​

+5

k

^

Q(3,4,5)=3

i

^

+4

j

^

​

+5

k

^

Now the distance between them=(3

i

^

+4

j

^

​

+5

k

^

)−(2

i

^

+3

j

^

​

+5

k

^

)

=

i

^

+

j

^

​