Question

What is the distance between (3,10) and (3,−8) on a coordinate grid?

Answer 1

Step-by-step explanation:

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$Your answer:-$

Let A(3,10) & B(3,-8)

AB=√(x2²-x1²)+(y2²-y1²)

= √(3²-3²)+(-8²-10²)

=√0+(64-100)

=√-36

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Answer 2

$\huge{\bold{ Question:-}}$

$what \: is \: the \: distance \: between \: (3 \: 10) \: and \: (3 \: - 8) \\ on \: a \: coordinate ?\\ \\ \huge{\bold{ Solution:-}} \\ \\ Let \: P(x1 ,\: y1) = (3, \: 10) \: and \: Q(x2, \: y2) = (3, \: - 8) \\ \\ by \: distance \: formula \\ \\ PQ = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } \\ \\ = \sqrt{( {3 - 3)}^{2} + ( { - 8 - 10)}^{2} } \\ \\ = \sqrt{0 + ( { - 18)}^{2} } \\ \\ = \sqrt{224} \\ \\ = \sqrt{18 \times 18} \\ \\ = 18$

${\red{\small{\underline{\mathbb{Distance = 18}}}}}$

Hope its helpful ❤