Question

what is the distance between minima on either side of screen in ydse​

Answer 1

Explanation:

In YDSE,the formula for bright fringes (constructive interference) is:

yn=dnλD for nth bright fringe

Initially, D=1.5m

λ=500nm=500×10−9m

n=2

y2=10mm=10×10−3m=10−2m

Substituting: d=10−22×500×10−9×1.5

=1500×10−7=1.5×10−4m

Now,if λ=550nm:

y2′=1.5×10−42×550×10−9×1.5

=1100×10−5=1.1×10−2m  

Shift =y2′−y2=1.1×10−2−1×10−2

=10−2(1.1−1)=

Answer 2

Answer:

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