Question

what is the distance covered by a free falling body during the first three second of its motion​

Answer 1

Use th formula S = ut + 1/2 at^2 where, u=0 (No initial speed/ velocity), a= g= 10 m/s^2

Then you will get S = 0 + 1/2 *10 * 9

Therefore, S = 45metres

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