Question

What is the distance covered by a freely falling body during the 1st second pg its motion (g=32'/s²)

Answer 1

Answer:

Lets line up what we know so far(assuming the body starts from rest):

a = -10

u = 0 (initial velocity)

t = 1

we want to find S (some people use X for distance), so we use the formula S = u*t + 0.5*a*t^2

Therefore S = 0*1 + 0.5*-10*1 = -5

It has moved -5m, in other words, moved downwards five meters.