Question

What is the distance covrd by a freely falling body during the first three second of its motion

Answer 1

acceleration= 10 m/second square
time = 3 second
initial velocity= 0m/s
distance covered=?
Since, s= ut + 1/2at×t
s= 0×3 + 1/2×10×3×3
s= 0+ 1/2×90
s= 45m.