Question

What is the distance of point p(-3,2) from y-axis?
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Answer 1

Answer:

the x-coordinate is '-3' and y -coordinate is '2'.

As, the distance of a point from the 'y' axis is the 'x' coordinate which is -3. Therefore, the distance of the point p(-3,2) is -3 units.

Answer 2

Answer:

Distance between the point P( - 3 , 2 ) from y-axis is 3 units.

Step-by-step explanation:

Here, the perpendicular distance can be determined, by using the distance formula.

Distance formula : Distance between points A( a , b ) and X( x , y ) is given by using : - √{ ( a - x )^2 + ( b - y )^2 } .

If we draw a perpendicular from P( - 3 , 2 ) on y-axis, coordinates of the new points on perpendicular will be ( 0 , 2 ) { since it's being drawn on Y-axis, x- coordinate will be 0 , and y- coordinate will be 2 , since we have drawn a perpendicular from the containing 2 as y-coordinate }.

Distance between P( - 3 , 2 ) and ( 0 , 2 ) = √{ ( - 3 - 0 )^2 + ( 2 - 2 )^2 }

= > √( - 3 )^2

= > √9

= > 3 { Distance can't be negative }

Thus distance between the point P( - 3 , 2 ) from y-axis is 3 units.