Math, asked by Pickatchu2307, 1 year ago

In a culture of yeast the active ferment doubles itself in 3 hours. Assuming that the quantity increases at a rate proportional to itself, determine the number of times it multiplies itself in 15 hours.

Answers

Answered by aashi2701
5

Let x = initial growth rate 

  2x = growth rate at 1 hour

2.75 is 2 3/4 hours, 3/4 hour is 3/4 x 60 = 45 minutes


total time = 60(2) +45 = 165 minutes 

by ratio and proportion;



? = 5.5x


therefore, the original amount will increase 5.5 times in just 2.75 hours, amazing! 



Answered by amitnrw
2

Answer:

32 times

Step-by-step explanation:

In a culture of yeast the active ferment doubles itself in 3 hours. Assuming that the quantity increases at a rate proportional to itself, determine the number of times it multiplies itself in 15 hours.

Let say at beginning Fermant = F

in next 3 hours it get doubled so becomes = 2F

in Further next 3 hours( total 6 hours) it gets doubled again so it becomes = 2 * 2F =  4F

in Further next 3 hours( total 9 hours) it gets doubled again so it becomes = 2 * 4F =  8F

in Further next 3 hours( total 12 hours) it gets doubled again so it becomes = 2 * 8F =  16F

in Further next 3 hours( total 15 hours) it gets doubled again so it becomes = 2 * 16F =  32F

So it multiplied 32 times itself in 15 hours

or Simply it multiplies = 2^(15/3) =  2⁵ = 32

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