Question

What is the distance of the point P(15,36) from the origin?

Answer 1

x1 = 0 and x2 = 15

y1 = 0 and y2 = 36

$d = \sqrt{( {x2 - x1) }^{2} + ( {y2 - y1)}^{2} }$

$d = \sqrt{ {(15 - 0)}^{2} + ( {36 - 0)}^{2} }$

$d = \sqrt{ {(15)}^{2} + {(36)}^{2} }$

$d = \sqrt{225 + 1296}$

$d = \sqrt{1521}$

$d = 39 \: unit$

therefore the distance of the point P( 15,36 ) is 39 units

Answer 2

The distance of the point P(15,36) from the origin  is 39 units

Step-by-step explanation:

we have to find the distance from the origin(0,0) to the point P (15,36)

using the distance formula

taking $x_1 = 0$

$y_1=0$

$x_2= 15$

$y_2= 36$

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d= \sqrt{(15-0)^2+(36-0)^2}$

$d= \sqrt{(15)^2+(36)^2}$

$d= \sqrt{225+1296}$

$d=\sqrt{1521}$

$d=\sqrt{3\times3\times13\times13}$

d= 3×13

d= 39 units

hence,

The distance of the point P(15,36) from the origin  is 39 units

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