Question

what is the distance travel led by the body starting from rest if it accelerates with 10/sec sq. for 2 sec

Answer 1

Answer:

20 m

Explanation:

Given,

a = 10 m/s

t = 2 seconds

u = 0(Initial Velocity)

Apply the equation of motion

v = u + at

  = 0 + 10 * 2

  = 20 m/s

Now,

The distance travelled in the 2 seconds is :

s = ut + (1/2) at^2

  = 0 + (1/2) * 10 * 2^2

  = 20 m

Therefore,

Distance traveled = 20 m

Hope it helps!

Answer 2

Gɪᴠᴇɴ :-

• Initial velocity (u) = 0 --(At rest)
• Acceleration (a) = 10m/s²
• Time taken (t) = 2 seconds

ᴛᴏ ғɪɴᴅ :-

• Distance travelled (s)

sᴏʟᴜᴛɪᴏɴ :-

On using 2nd equation of motion, we get,

➥ s = ut + 1/2 at²

➱ s = 0×t + 1/2 × 10 ×(2)²

➱ s = 1/2 × 10 × 4

➱ s = 40/2

➱ s = 20 m

Hence,

• Distance travelled (s) = 20m