Question

What is the domain and range of f(x)=x^2+3x+2?

Answer 1

Answer:

Domain = R

range of f(X) = [-1/4, infinity)

Step-by-step explanation:

as it is a quadratic equation so it domain is R

and for the range

f(x) = x^2 + 3x + 2

f'(x) = 2x + 3 =0

x = -3/2

now put X = 3/2 in f(x)

9/4 - 9/2 +2

= 2 - 9/4

= -1/4

so the range of f(X) = [-1/4, infinity)