Question

What is the electric flux through a cube of side 1 cm which encloses an electric charge of 100 micro.

Answer fast it is urgent......

Shivika Tiwari...​

Answer 1

HEYA

Here's your expected answer...

Please let me know if there's any error.

TC

Answer 2

Answer:

• The electric flux (∅) is 11.3 × 10⁶ Nm/C

Given:

1. Charge Enclosed (Q) = 100 μ C.
2. Side of cube (a) = 1 cm.

Explanation:

$\rule{300}{1.5}$

From the Relation we know,

$\bigstar\;\underline{\boxed{\sf \phi=\oint \sf E.da=\dfrac{Q_{\;(enc)}}{\epsilon_{o}}}}$

Here,

• ∅ Denotes Electric flux.
• E Denotes Electric field.
• Q Denotes Charge enclosed.
• ε₀ Denotes Permittivity of free space.

As, given that the charge is present inside the cube,

Therefore,

$\displaystyle\longrightarrow\sf \phi=\dfrac{Q}{\epsilon_{o}}$

Where,

• Q = 100 μ C.
• ε₀ = 8.85 × 10⁻¹² C²/N-m²

Substituting the values,

$\displaystyle\longrightarrow\sf \phi=\dfrac{100\;\mu C}{8.85\times 10^{-12}}\\\\\\\longrightarrow\sf \phi = \dfrac{100\times 10^{-6}}{8.85\times 10^{-12}}\\\\\\\longrightarrow\sf \phi=\dfrac{100\times 10^{-6}\times 10^{12}}{8.85}\\\\\\\longrightarrow\sf \phi=\dfrac{100\times 10^{\;-6\;+\;12}}{8.85}\\\\\\\longrightarrow\sf \phi=\dfrac{100}{8.85}\times 10^{6}\\\\\\\longrightarrow\sf \phi=11.3\times 10^{6}\\\\\\\longrightarrow\large{\underline{\boxed{\red{\sf \phi= 11.3\times 10^{6}\;Nm/C }}}}$

∴ The electric flux (∅) is 11.3 × 10⁶ Nm/C

$\rule{300}{1.5}$