Question

what is the electric flux through a cube of side 1 cm which encloses an electric dipole?

Answer 1

side 1cm = 0.01m
area=0.01×0.01= 0.0001msquare
flux=b×a

Answer 2

Hey !!

Zero ( as net charge enclosed by the surface is zero ).

DETAILED EXPLANATION

In a cubic surface, the net electric charge will be zero since dipole carries equal and opposite charges. It is observed that the net electric flux through closed surface will be

                                         = Charge enclosed / ε₀

and because the charge enclosed is zero.

  electric flux is also zero.

Good luck !!