Question

what is the electric force between two small charged spheres having charges of 2×10^7 C and 3×10^7 C placed 30 cm apart in air ?

please solve with full calculation ​

Answer 1

Answer:

6 x 10²⁵ N

Explanation:

F(electrostatics) = kq₁q₂/r²

Here,  q₁ = 2 x 10⁷   &  q₂ = 3 x 10⁷  

r = 30 cm = (30/100) m = 0.3 m

∴ F = kq₁q₂/r²  

     = (9 x 10⁹)(2 x 10⁷)(3 x 10⁷)/(0.3)²

     = (9 x 2 x 3 x 10²³)/(0.09)

     = 6 x 10²⁵ N

Note that if q₁ = 2 x 10⁻⁷   &  q₂ = 3 x 10⁻⁷

   answer is 6 x 10⁻³ N  following the same procedure.

Answer 2

Given :-

Charges of 2×10^7 C and 3×10^7 C

To find :-

Electric force

Solution :-

We know that

$\bf \red{F_E = \dfrac{q_1q_2}{4 \pi e_0r^2} }$

Here

$\sf e_0 = The\; free\; space$

$\sf F_E = \dfrac{2\times 10^{-7} \times 3\times 10^{-7}}{9 \times 10^9 \times (0.3)^2}$

$\sf F_E = \dfrac{9 \times 10^9 \times 2 \times 10^{-7} \times 3\times 10^{-7}}{(0.3)^2}$

$=\sf F_E = \dfrac{9 \times 10^9 \times 2 \times 10^{-7} \times 3\times 10^{-7}}{(0.09)}$

$\sf F_E = 6\times 10^{-3} N$