What is the electric potential at the surface of a gold nucleus? The radius is 6.6×10-15
m and the atomic number Z=79
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Answer:
The electric potential at the surface of the gold nucleus is given as
V=
4πε
0
r
Ze
By substituting the values in the above equation we get
V=
6.6×10
−5
9×10
9
×79×1.6×10
−19
V=172.3×10
−5
Hence, the electric potential is 172.3×10
−5
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