Question

what is the electronic configuration of rubidium ?

Answer 1

Answer:  $Rb:37:[Kr]4s^1$

Explanation:-

Rubidium is an element with atomic number 37 and thus contain 37 electrons. It is a s block element as the last electron enters the s orbital. The nearest noble gas is Krypton with 36 electrons.

The electrons are filled according to Afbau's rule in order of increasing energies and thus the electronic configuration in terms of noble gs energies and thus the electronic configuration in terms of noble gs configuration is:  

$Rb:37:[Kr]4s^1$ or

$Rb:37:1s^22s^22p^63s^23p^63d^{10}4s^1$

Answer 2

Answer:

[kr] 5 s¹

Explanation:

+@(3+81+#;1!9$+2