Physics, asked by sakshikhomane, 11 months ago

what is the emmisive power of perfect blackbody at 1000K

Answers

Answered by heroboy53
16

Answer:

Emittance (or emissive power) is the total amount of thermal energy emitted per unit area per unit time for all possible wavelengths. Emissivity of abody at a given temperature is the ratio of the total emissive power of a body to the totalemissive power of a perfectly black body at that temperature.

Answered by kingofself
7

The emmisive power of perfect blackbody at 1000K is 230 \frac{j}{\frac{m^2}{s}}

Explanation:

  • When a certain Opaque object or artefact can follow the rules and laws of radiation that are related thermally then the subject are termed as black body.
  • When a black body is taken into consideration then it shall absorb all the radiations are energy that are being produced on it and will emit the least possible.
  • If it is considered as perfect then the emission of radiation will be near to zero.
  • The temperature of the body is given as 1000 degrees kelvin and the emissive power will be E = \frac{Q}{(t \times a)}

                                                              ⇒ \frac{1380}{3 \times 2}

                                                   = 230 \frac{j}{\frac{m^2}{s}}.

To know more:

What is the emissive power of a perfect blackbody at 1000 K?​

https://brainly.in/question/13576334

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